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A certain car traveling at 97 km/h can stop in 47 m on a level road find the coefficient of friction

Sagot :

Onyebuchinnajiidn

The coefficient of friction between the road and the car's tire is determined as 0.78.

Acceleration of the car

The acceleration of the car is calculated as follows;

v² = u² - 2as

0 = u² - 2as

a = u²/2s

where;

  • u is the initial velocity = 97 km/h = 26.94 m/s

a = (26.94)²/(2 x 47)

a = 7.72 m/s²

Coefficient of friction

μ = a/g

μ = (7.72)/9.8

μ = 0.78

Learn more about coefficient of friction here: https://brainly.com/question/14121363

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