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write a Pythagorean triplet whose smallest member is 6​

Sagot :

Tot1466idn

Answer:

6, 8, 10

Step-by-step explanation:

Where:

a = 6

b = 8

c = 10

Pythagorean theorem: [tex]a^2 + b^2 = c^2[/tex]

[tex]6^2 + 8^2 = c^2[/tex]

[tex]36 + 64 = c^2[/tex]

[tex]100 = c^2[/tex]

c = [tex]\sqrt{100}[/tex]

c = 10

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