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Write the equation of the graph of y = cos(x) was shifted downwards by 3 units, shrink horizontally by a fourth of a unit, inverted horizontally and shifted 60° to the left. if it has an amplitude of 5 units.


Sagot :

The equation of the transformed function is y = 5cos(x/4 + 60) - 3

How to determine the equation?

The equation of the graph is given as:

y = cos(x)

The rule of downward shift is:

(x, y) ⇒ (x, y - h)

So, the function when shifted downwards by 3 units is

y = cos(x) - 3

The rule of horizontal shrink is:

(x, y) ⇒ (x/k, y)

So, the function when shrink horizontally by a fourth unit is:

y = cos(x/4) - 3

The rule of left shift is:

(x, y) ⇒ (x +h, y)

So, the function when shifted left by 60 units is

y = cos(x/4 + 60) - 3

The amplitude is given as:

A= 5

So, we have:

y = 5cos(x/4 + 60) - 3

Hence, the equation of the transformed function is y = 5cos(x/4 + 60) - 3

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