Discover the best answers to your questions with the help of IDNLearn.com. Ask your questions and receive prompt, detailed answers from our experienced and knowledgeable community members.
Sagot :
Answer:
- David: $42
- Mary: $70
Step-by-step explanation:
The two relations can be translated to a system of linear equations in two variables. These can be solved in any of the usual ways.
__
setup
Let d and m represent the amounts David and Mary saved last month, respectively.
The first relation tells us
d/m = 3/5 ⇒ 5d = 3m ⇒ 5d -3m = 0
The second relation tells us that adding 3 times what David had last month to 2 times what Mary had last month will give a total that is 154 greater than the sum of their funds last month.
d +m + 154 = 3d +2m ⇒ 2d +m = 154
__
solution
We can add 3 times the second equation to the first to eliminate m.
(5d -3m) +3(2d +m) = (0) +3(154)
11d = 462 . . . . . . . . simplify
d = 42 . . . . . . . . . divide by 11
Using the second equation, we can find Mary's savings:
m = 154 -2d
m = 154 -2(420 = 70
David saved $42 last month; Mary saved $70.
We appreciate your participation in this forum. Keep exploring, asking questions, and sharing your insights with the community. Together, we can find the best solutions. Your search for solutions ends here at IDNLearn.com. Thank you for visiting, and come back soon for more helpful information.