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A grocery wants to make two kinds of coffee. One consoles for $1.40 pound, and the other cells for $2.95 a pound. He wants to makes a total of 21 pounds and sell it for $2.60 per pound. How many pounds of each kind should he use in the new mix? (round off the answers to the nearest hundredth)

Sagot :

Reinhard10158idn

Step-by-step explanation:

a lot of typos in the problem description.

I assume the price of the mix is 1:1 related to the prices of the individual types of coffee.

so, from what I understood we can define

x = pounds of the first type of coffee.

y = pounds of the second type of coffee.

x + y = 21 pounds

1.4x + 2.95y = 2.6(x + y) = 2.6×21 = $54.60

in the second equation we have to bring the given "$2.60 per pound" to the total price, which is $2.60 times the total amount of pounds (which is 21).

from the first equation we get

x = 21 - y

and that we use in the second equation

1.4×(21 - y) + 2.95y = 54.6

29.4 - 1.4y + 2.95y = 54.6

1.55y = 25.2

y = 25.2 / 1.55 = 16.25806452... ≈ 16.26 pounds

x = 21 - y = 4.741935484... ≈ 4.74 pounds

so, he should mix 4.74 pounds of the first (cheaper) type and 16.26 pounds of the second (expensive) type.

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