Breframpton92105idn
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write the first six terms of the sequence f(n)=n^3+2​

Sagot :

Loneguyidn

Answer:

[tex]3,10,29,66,127,218[/tex]

Step-by-step explanation:

[tex]f(n) = n^3 +2\\\\f(1) = 1^3 +2 = 1+2=3\\\\f(2) =2^3 +2 = 8+2=10\\\\f(3)=3^3 +2 = 27+2 = 29\\\\f(4) = 4^3 +2 = 64 +2 = 66\\\\f(5) = 5^3 +2 = 125+2 = 127\\\\f(6) = 6^3 +2 = 216+2 = 218[/tex]

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