Aileen7Roseidn
Answered

Connect with experts and get insightful answers to your questions on IDNLearn.com. Our platform provides prompt, accurate answers from experts ready to assist you with any question you may have.

20 ml of a mixture of C2H6 and C3H8 gases in X : Y mole ratio, is burnt completely by which 52 ml CO2 gas is evolved. If 20 ml of a mixture of CH4 and C4H10 gases in Y : X mole ratio is burnt completely then what is the volume (in ml) of CO2 gas evolved?
A) 40 B) 44 C) 50 D) 55

Sagot :

Mickymike92idn

The volume of CO2 prodiced when 12 mL of CH4 and 8 mL of C4H10 is burnt is 56 mL.

What is the equation of the reaction?

The equation of the combustion of C2H6, CH4, C4H10, and C3H8 gases are given below:

2 C2H6 + 7 O2 ---> 4 CO2 + 6 H20

C3H8 + 5 O2 ---> 3 CO2 + 4 H20

CH4 + 2 O2 ----> CO2 + 2 H2O

2 C4H10 + 13 O2 ---> 8 CO2 + 10 H2O

X moles of C2H6 will produce 2X moles of CO2

Y moles of C3H8 will produce 3Y moles of CO2

Thus;

X + Y = 20 mL

X =20 - Y ---(1)

2X + 3Y = 52 mL ---(2)

Solving for X by substituting in (2)

2 (20 - Y) + 3Y = 52

40 - 2Y + 3Y = 52

Y = 12 mL

Then X = 8 mL

Volume of CO2 produced when 12 mL of CH4 and 8 mL of C4H10 is burnt = (12 × 2 + 8 × 4) = 56 mL

Therefore, the volume of CO2 produced is 56 mL.

Learn more about moles of gas and volume at: https://brainly.com/question/23883946

#SPJ1

We greatly appreciate every question and answer you provide. Keep engaging and finding the best solutions. This community is the perfect place to learn and grow together. IDNLearn.com is committed to providing accurate answers. Thanks for stopping by, and see you next time for more solutions.