Answered

IDNLearn.com is the perfect place to get answers, share knowledge, and learn new things. Find the answers you need quickly and accurately with help from our knowledgeable and experienced experts.

A body of mass 250g is release from the top of a building. if the body hits the ground with a velocity of 4m/s, calculate th height of the building [g=10m/s²]​

Sagot :

TwinklingStaridn

[tex]\purple{\maltese}\large\underline{\underline{\sf\:\: Given :}} \\ [/tex]

» Mass ( m ) of the body = 250 g

» final velocity of the body = 4 m/s

[tex]\\\purple{\maltese}\large\underline{\underline{\sf\:\: To \: \: Find :}} \\ [/tex]

» The height of the Building= ??

[tex]\\\purple{\maltese}\large\underline{\underline{\sf\:\: Solution :}} \\ \\[/tex]

★ Height of the building by the principal of conservation;

[tex]\\\\\begin{gathered}\purple{\maltese}\large\underline{\underline{\sf\:\: using \: formula :}} \\ \\\end{gathered}[/tex]

[tex] \bigstar \: \underline{ \boxed{\sf { \pink{ \: \frac{1}{2} \: \: mv { }^{2} = \: mgh \: }}}} [/tex]

[tex]\\ \: \: \underline{\textsf {Putting values \: in \: the \: \: given \: formula :}} \\ [/tex]

[tex] \\ \sf \implies \: \frac{1}{2} \: \: mv { }^{2} = \: mgh \: \\ [/tex]

[tex] \\ \sf \implies \: \frac{v {}^{2} }{2} \: \: = \: gh \: \\ [/tex]

[tex] \\ \sf \implies \: h \: = \frac{v {}^{2} }{2g} \: \: \: \\ [/tex]

[tex] \\ \sf \implies \: h \: = \frac{16 }{20} \: \: \: \\ [/tex]

[tex] \\ \sf \implies \: h \: = 0.8 \: \: \: m \\ [/tex]

[tex] \\ \sf \implies \: h \: = 80 \: \: \: cm \\ [/tex]

henceforth , The height of the Building is 0.8 m or 80 cm ..!!!

We appreciate your presence here. Keep sharing knowledge and helping others find the answers they need. This community is the perfect place to learn together. IDNLearn.com provides the best answers to your questions. Thank you for visiting, and come back soon for more helpful information.