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Question 9 (5 points)
Which is the equation of the line for the points in the given table?
X
-4 2 6
y
13 -5 -17
On y= -2x-1
OB) y = -2x+5
OC) y = -2x - 5
OD) y=-3x + 1

Question 9 5 Points Which Is The Equation Of The Line For The Points In The Given Table X 4 2 6 Y 13 5 17 On Y 2x1 OB Y 2x5 OC Y 2x 5 OD Y3x 1 class=

Sagot :

to get the equation of any straight line, we simply need two points off of it, let's use those two points from the table in the picture below.

[tex](\stackrel{x_1}{-4}~,~\stackrel{y_1}{13})\qquad (\stackrel{x_2}{6}~,~\stackrel{y_2}{-17}) \\\\\\ \stackrel{slope}{m}\implies \cfrac{\stackrel{rise} {\stackrel{y_2}{-17}-\stackrel{y1}{13}}}{\underset{run} {\underset{x_2}{6}-\underset{x_1}{(-4)}}} \implies \cfrac{-30}{6 +4} \implies \cfrac{ -30 }{ 10 }\implies -3[/tex]

[tex]\begin{array}{|c|ll} \cline{1-1} \textit{point-slope form}\\ \cline{1-1} \\ y-y_1=m(x-x_1) \\\\ \cline{1-1} \end{array}\implies y-\stackrel{y_1}{13}=\stackrel{m}{-3}(x-\stackrel{x_1}{(-4)}) \\\\\\ y-13=-3(x+4)\implies y-13=-3x-12\implies y=-3x+1[/tex]

View image Jdoe0001
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