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PLEASE HELP ASAP WILL MARK BRAINLY

PLEASE HELP ASAP WILL MARK BRAINLY class=

Sagot :

  • tanØ=Perpendicular/Base

Mark the lines

  • tanD=BC/BD

Put the values

  • tanD=√38/√53

Done

Semsee45idn

Answer:

[tex]\sf \tan(D)=\dfrac{\sqrt{38}}{\sqrt{53}}[/tex]

Step-by-step explanation:

Tangent trigonometric ratio

[tex]\sf \tan(\theta)=\dfrac{O}{A}[/tex]

where:

  • [tex]\theta[/tex] is the angle
  • O is the side opposite the angle
  • A is the side adjacent the angle

Given:

  • [tex]\theta[/tex] = D
  • O = √38
  • A = √53

Substituting the given values into the formula:

[tex]\implies \sf \tan(D)=\dfrac{\sqrt{38}}{\sqrt{53}}[/tex]

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