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In circle B below, diameter RT, radius BE, and chord RE are drawn.
If m2TRE = 15° and BE = 9, then the area of sector EBR is

Sagot :

Akposevictoridn

The area of sector EBR in the given diagram attached below is: 33.75π units².

What is the Area of a Sector?

Area = θ/360º × πr²

Given the following:

  • m∠TRE = 15°
  • BE = 9

Measure of arc TE = 2(m∠TRE) = 2(15) [inscribed angle theorem]

Measure of arc TE = 30°

Arc RE = 180 - arc TE = 180 - 30 [semicircle]

Arc RE = 150°

m∠EBR = Arc RE = 150°

Area of sector EBR = m∠EBR/360 × π(BE²)

Area of sector EBR = 150/360 × π(9²)

Area of sector EBR = 33.75π units²

Learn more about the area of sector on:

https://brainly.com/question/22972014

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View image Akposevictor
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