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1. Suppose that a sample of beef broth initially contains
16 bacterial cells. After 4.0 h, there are 1.6 × 106
bacterial cells in the sample. Assuming that the
bacteria reproduce at a constant rate, calculate the
growth rate of the bacterial population for the given
time interval.

Sagot :

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From the calculations, the rate of growth of the culture is 2.88.

What is exponential growth problem?

We apply the exponential growth problem when there is an exponential increase.

Thus, we have; P =Poe^rt

P = amount at time t

Po = amount originally present

t = time taken

r = rate of growth

1.6 × 10^6 = 16e^4r

1.6 × 10^6/16 = e^4r

1.0 * 10^5 =  e^4r

ln 1.0 * 10^5 = ln e^4r

11.5 = 4r

r = 11.5/4

r = 2.88

Learn more about exponential growth:https://brainly.com/question/11487261

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