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Sagot :
1.41 × 10³⁰ MeV
As we know, E=mc², where E is energy, m is mass and c is the speed of light(i.e. 3×10⁸ m/s).
Given mass = 2.5 kgs
∴ E = (2.5)×(3×10⁸)² J = 22.5×10¹⁶ J
As our answer is in joules so we have to convert it into mega electron volt(MeV)
1 J = 6.242 × 10¹² MeV
⇒ 22.5×10¹⁶ J = 22.5×10¹⁶ × (6.242 × 10¹²) MeV
⇒1.41 × 10³⁰ MeV
If you want to learn more about mass-energy conversions then you can check out this link:
https://brainly.in/question/9760064
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