Malhefeiti696idn
Answered

Find solutions to your problems with the help of IDNLearn.com's knowledgeable users. Ask your questions and receive detailed and reliable answers from our experienced and knowledgeable community members.

a straight current-carrying wire in a uniform magnetic field, oriented at right angles to the wire. The 0.25-m wire carries a 4.75-A current and experiences a force of 0.38 N. What is the strength of the magnetic field?
0.45 T
0.56 T
0.32 T
0.72 T

Sagot :

Leenaidn

Hello!

Using the equation for the magnetic force on a current-carrying wire:
[tex]F_B = \vec{B} \times i\vec{L}[/tex]

[tex]F_B[/tex] = Magnetic Force (0.38 N)
B = Magnetic field strength (T)
i = Current in wire (4.75 A)
L = Length of wire (0.25 m)

This is a cross product, so we can rewrite the equation as:
[tex]F_B = BiLsin\phi[/tex]

Where φ is the angle between the magnetic field vector and the length vector. In this instance, since the field is perpendicular to the wire, sin(90) = 1. We can simplify the equation to:
[tex]F_B = BiL[/tex]

Rearrange the equation to solve for 'B':
[tex]B = \frac{F_B}{iL}[/tex]

Plug in given values and solve.

[tex]B = \frac{0.38}{(4.75 * .25)} = \boxed{0.32 T}[/tex]

The strength of the magnetic field will be 0.32 T.Option B is correct.

What is magnetic field strength?

The number of magnetic flux lines on a unit area passing perpendicular to the given line direction is known as induced magnetic field strength .it is denoted by B.

Given data:

(I) current = 4.75-A

(B)induced magnetic field strrength=?

(L)length of the wire=0.25-m

(F)Magnetic force=0.38 N

The strength of the magnetic field is found as:

[tex]\rm F_B=BILsin \theta \\\\\ \theta = 90^0 \\\\ \rm F_B=BIL \\\\[/tex]

Substitute the values:

[tex]\rm 0.38 = B \times 4.75 \times 0.25 \\\\\ B= \frac{0.38}{4.75 \times 0.25 } \\\\\ B=0.32 \ T[/tex]

The strength of the magnetic field will be 0.32 T.

Hence, option B is correct.

To learn more about the strength of induced magnetic field refer ;

https://brainly.com/question/2248956

#SPJ1

We appreciate every question and answer you provide. Keep engaging and finding the best solutions. This community is the perfect place to learn and grow together. Find precise solutions at IDNLearn.com. Thank you for trusting us with your queries, and we hope to see you again.