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Sagot :
The required equation of the line is 5y=x.
We are given to find the equation of the line passing through the points (0, 0) and (15, 3).
We know that
What is the slope point form of the line?
The equation of a line passing through two points (a, b) and (c, d) is given by
[tex]y-b=\frac{d-b}{c-a}(x-a)[/tex]
Therefore, the equation of the line passing through the points (0, 0) and (15, 3) is given by,
Thus, the required equation of the line is
[tex]y-0=\frac{3-0}{15-0}(x-0)\\y=\frac{3}{15}x\\ y=\frac{1}{5}x\\ 5y=x[/tex]
Thus the required equation of the line is 5y=x.
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