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[tex]\displaystyle |\Omega|=\binom{40}{2}=\dfrac{40!}{2!38!}=\dfrac{39\cdot40}{2}=780\\|A|=\binom{10}{2}=\dfrac{10!}{2!8!}=\dfrac{9\cdot10}{2}=45\\\\P(A)=\dfrac{45}{780}=\dfrac{3}{52}\approx5,8\%[/tex]