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IB Chemistry - Stoichiometry
In which mixture is NaOH the limiting reagent?

A. 0.20 mol NaOH + 0.10 mol H2SO4
B. 0.10 mol NaOH + 0.10 mol H2SO4
C. 0.20 mol NaOH + 0.10 mol HNO3
D. 0.10 mol NaOH + 0.10 mol HNO3

Sagot :

In which mixture of 0.10 mol NaOH + 0.10 mol [tex]H_2SO_4[/tex], NaOH is the limiting reactant. Hence option B is correct.

What is a limiting reagent?

The limiting reagent is the reactant that is completely used up in a reaction, and thus determines when the reaction stops.

Reaction

[tex]2NaOH + H_2SO_4[/tex] → [tex]Na_2SO_4 + 2H_2O[/tex]

For one mole of [tex]H_2SO_4[/tex] we need two moles of NaOH.

Option A: equivalent quantities

Option B: NaOH is limiting rectant.

[tex]NaOH + HNO_3[/tex] → [tex]NaNO_3+ H_2O[/tex]

For one mole of [tex]HNO_3[/tex] we need one mole of NaOH.

Option C: NaOH in excess

Option D: equivalent quantities

In which mixture of 0.10 mol NaOH + 0.10 mol [tex]H_2SO_4[/tex], NaOH is the limiting reactant. Hence option B is correct.

Learn more about the limiting reagent here:

https://brainly.com/question/11848702

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