Explore IDNLearn.com to discover insightful answers from experts and enthusiasts alike. Discover detailed and accurate answers to your questions from our knowledgeable and dedicated community members.

Check whether the following differential equation is exact or not. If not, then convert it into an exact differential equation.

[tex]2ydx+(x-sin\ y^{\frac{1}{2} } )dy =0[/tex]


Sagot :

The given differential equation is not exact, if we convert it to an exact one, we get:

[tex]2ydx + 2*(x - sin(y)^{1/2})*dy = 0[/tex]

Is the differential equation exact or not?

A differential equation:

[tex]Ndx + Mdy = C[/tex]

Is exact only if:

[tex]\frac{dM}{dy} = \frac{dN}{dx}[/tex]

In this case, we have:

[tex]2ydx + (x - sin(y)^{1/2})*dy = 0\\\\then:\\\\N = 2y\\M = x - sin(y)^{1/2}[/tex]

If we differentiate, we will get:

[tex]\frac{dN}{dy} = 2\\\\\frac{dM}{dx} = 1[/tex]

So, to convert this to an exact differential equation, we need to add a factor 2 to N, this will give:

[tex]2ydx + 2*(x - sin(y)^{1/2})*dy = 0[/tex]

This is, in fact, an exact differential equation.

If you want to learn more about differential equations:

https://brainly.com/question/18760518

#SPJ1