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Solve 8x+5y=2 and y-2=0.Also verify thmm....​

Sagot :

Seolleaphroditeidn

Answer:

Solution: Here, the given equations are,

[tex]: \implies8x+5y=2...(i)\:and\:y-2=0...(ii)[/tex]

From equation,(ii); y-2=0

[tex] \therefore \: y = 2.........(iii)[/tex]

Substituting the value of y from equation (iii) to equation (i),we get

[tex]: \implies{8x + 5y = 2}[/tex]

[tex]: \implies{8x + 5(2) = 2}[/tex]

[tex]: \implies{8x = 2 - 10}[/tex]

[tex]: \implies{8x = - 8}[/tex]

[tex]: \implies{x = - 1}[/tex]

[tex] \therefore \: x = - 1[/tex]

Thus, x= -1 and y= 2 is the solution.

  • Checking at (-1,2)

8x+5y=2...(i) y-2=0...(ii)

8(-1)+5(2)=2 2-2=0

2=2(True) 0=0(True)

Sidharth999idn
Answer: x = -1, y = 2

Step-by-Step Explanation:

=> 8x + 5y = 2 (Eq. 1)
=> y - 2 = 0 (Eq. 2)

We can Solve Eq. 2 :-

y - 2 = 0
=> y = 2

Substitute value of ‘y’ in Eq. 1 :-

8x + 5y = 2
8x + 5(2) = 2
8x + 10 = 2
8x = 2 - 10
8x = -8
x = -8/8
=> x = -1

Therefore; x = -1, y = 2
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