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Sagot :
Hi student, let me help you out! :)
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We are asked to solve the equation [tex]\mathrm{-6z+2+3=15}[/tex].
[tex]\triangle~\fbox{\bf{KEY:}}[/tex]
- The goal is to isolate x.
Notice that we can add 2+3 right off the bat:
[tex]\star~\mathrm{-6z+5=15}[/tex]
Subtract 5 from both sides of the equal sign:
[tex]\star~\mathrm{-6z=10}[/tex]
Divide both sides by -6:
[tex]\star~\mathrm{z=\cfrac{10}{-6}}[/tex]
Simplify!
[tex]\star~\mathrm{z=-\cfrac{5}{3}}[/tex]
Hope it helps you out! :D
Ask in comments if any queries arise.
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