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A boy throws a toy up in the air with an initial velocity of 7.9 m/s at an angle of 37 degrees . what is the maximum height reached by the toy?

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The maximum height reached by the toy at the given velocity and angle of projection is determined as 1.15 m.

Maximum height reached by the toy

The maximum height reached by the toy is calculated as follows;

H = u²sin²θ/2g

where;

  • u is the initial velocity
  • θ is the angle of projection
  • g is gravity

H = (7.9² x (sin37)²)/(2 x 9.8)

H = 1.15 m

Thus, the maximum height reached by the toy at the given velocity and angle of projection is determined as 1.15 m.

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