Answered

Get detailed and reliable answers to your questions on IDNLearn.com. Our platform offers reliable and comprehensive answers to help you make informed decisions quickly and easily.

A metal sign for a car dealership is a thin, uniform right triangle with base length b and height h. the sign has mass m.

required:
a. what is the moment of inertia of the sign for rotation about the side of length h?
b. if m = 4.40 kg ,b = 1.30 m and h = 1.30 m , what is the kinetic energy of the sign when it is rotating about an axis along the 1.30-m side at 2.40 rev/s ?

Sagot :

Onyebuchinnajiidn

(a) The moment of inertia of the sign for rotation about the side of length h is 1.24 kgm².

(b) The kinetic energy of the sign when it is rotating about an axis is 141.37 J.

Moment of inertia of the triangular sign

The moment of inertia of the sign for rotation about the side of length h is calculated as follows;

I = 2 x ¹/₃M(b/2)²

I = 2 x ¹/₃Mb² x ¹/₄

I = ¹/₆Mb²

I = ¹/₆ x 4.4 x 1.3²

I = 1.24 kgm²

Rotational kinetic energy of the ball

K.E(rot) = ¹/₂Iω²

where;

  • ω is angular speed = 2.4 rev/s = 2.4 x (2π rad)/s = 15.1 rad/s

K.E(rot) = ¹/₂(1.24)(15.1)²

K.E(rot) = 141.37 J

Learn more about rotational kinetic energy here: https://brainly.com/question/25803184

#SPJ1

We value your participation in this forum. Keep exploring, asking questions, and sharing your insights with the community. Together, we can find the best solutions. Your search for solutions ends at IDNLearn.com. Thank you for visiting, and we look forward to helping you again.