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What is the area of a regular pentagon with a side of 10 in.? round the answer to the nearest
tenth.
96.3in^2
172.0in^2
344.1in^2
192.6in^2
dont respond with a link!!!!!!

Sagot :

The area of the regular pentagon given a side of 10 in is 172.0 in².

What is the area?

A pentagon is an object that is made up of five sides. The sum of the internal angles of a pentagon is 540 degrees.

Area of a pentagon = 1/4√[tex]\sqrt{5 ( 5 + 2 \sqrt{5} ) }[/tex] a²

Where a = side = 10

A = 1/4√[tex]\sqrt{5 ( 5 + 2 \sqrt{5} ) }[/tex] 10²

A = 172.02 in²

To learn more about pentagons, please check: https://brainly.com/question/17054992

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