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If a line has a slope of 4 and contains the point (-2, 5), what is its equation in
point-slope form?
O A +5=4(x-2)
OB. J-5= 4(x-2)
C. + 2 = 4(x-5)
O D.y-5=4(x+2)

Sagot :

VectorFundament120idn

Answer:

y - 5 = 4(x + 2)

Step-by-step explanation:

Given:

  • Slope = 4
  • Point = (-2,5)

The point-slope form is in the form of [tex]\displaystyle \large{y-y_1=m(x-x_1)}[/tex]. Determine the followings:

  • m = slope = 4
  • (x1,y1) = point = (-2,5)

Therefore, input these in the formula.

[tex]\displaystyle \large{y-5=4[x-(-2)]}\\\\\displaystyle \large{y-5=4(x+2)}[/tex]

Therefore, the answer to this question is y - 5 = 4(x + 2)

Please let me know if you have any questions regarding my answer or explanation!

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