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Cylinder A has a radius of 10 inches and a height of 5 inches. Cylinder B has a volume of 750n. What is the percentage change in volume between cylinders A and B? Cylinder B is 50% smaller than cylinder A. Cylinder B is 75% smaller than cylinder A Cylinder B is 50% bigger than cylinder A Cylinder B is 200% bigger than cylinder A

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Fieryanswererftidn

Answer: Cylinder B is 50% bigger than cylinder A

Cylinder A volume:

= πr²h

= π(10)²(5)

= 500π

Cylinder B volume:

= 750π

Cylinder B bigger than Cylinder A by:

= (750π - 500π)/500π × 100 = 50%

[tex]\hrulefill[/tex]

Hence, cylinder B is bigger than cylinder A by 50%

Semsee45idn

Answer:

Cylinder B is 50% bigger than Cylinder A

Step-by-step explanation:

[tex]\textsf{Volume of a cylinder}=\sf \pi r^2 h \quad\textsf{(where r is the radius and h is the height)}[/tex]

Cylinder A

Given:

  • r = 10 in
  • h = 5 in

Substituting the given values into the formula:

[tex]\implies \sf Volume_A=\pi (10)^2(5)=500\pi \:in^3[/tex]

Cylinder B

Given:

  • volume = 750 in³

[tex]\implies \sf Volume_B=750\pi \:in^3[/tex]

Percentage Change

[tex]\begin{aligned}\sf percentage\:change & =\sf \dfrac{final\:value-initial\:value}{initial\:value} \times 100\\\\& = \sf \dfrac{Volume_B-Volume_A}{Volume_A} \times 100\\\\& = \sf \dfrac{750\pi-500\pi}{500\pi} \times 100\\\\& = \sf \dfrac{1}{2} \times 100\\\\& = \sf 50\%\end{aligned}[/tex]

Therefore, Cylinder B is 50% bigger than Cylinder A

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