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A motor with a power of 7.0 × 104 watts lifts a loaded elevator to a height of 20.00 meters for 40 seconds. what is the force exerted by the motor on the elevator? a. 1.4 × 104 newtons b. 7.0 × 104 newtons c. 1.4 × 105 newtons d. 2.1 × 105 newtons e. 3.5 × 105 newtons

Sagot :

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Answer:

  c.  1.4×10^5 N

Explanation:

Work is the product of power and time. It is also the product of force and distance. We can equate these two products to find the distance.

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  Wt = Fd

  (7.0×10^4 N·m/s)(40 s) = F(20 m)

  F = (7.0×10^4)(40/20) N = 1.4×10^5 N

The force exerted by the motor is 1.4×10^5 newtons.

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