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The probability that the ball we remove at the 11th round is blue will be 0.6.
From the information given, we remove a random ball and replace it with a new red ball. for example, after the first round we have 9 blue balls and one red ball.
Since we have 9 blue balls and remove one every round. Let's assume that the number of blue and red balls will be 6 and 4 respectively in the 11 the round
Therefore, the probability that the ball we remove at the 11th round is blue will be:
= 6/(6 + 4)
= 6/10
= 0.6
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