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Ampère placed two 1.50-m wires parallel to each other so that they were 4.80 cm apart.
He delivered a current of 6.50 A to the wires. Both wires experienced an external
magnetic field of 2.71 X 10^−5 T. Determine the force on one of the wires.

Ampère Placed Two 150m Wires Parallel To Each Other So That They Were 480 Cm Apart He Delivered A Current Of 650 A To The Wires Both Wires Experienced An Extern class=

Sagot :

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The force on one of the wires is determined as 1.76 x 10⁻⁴ N/m.

Force on the wire

The force between the two parallel wire is calculated as follows;

F = μI²L/2πr

where;

  • I is the current in the two wires
  • L is length of the wires
  • r is the distance between the wires

F = (4π x 10⁻⁷ x 6.5² x 1.5)/(2π x 0.048)

F = 2.64 x 10⁻⁴ N

Force per unit length of the wire

F/L =  2.64 x 10⁻⁴ N / 1.5

F/L = 1.76 x 10⁻⁴ N/m

Thus, the force on one of the wires is determined as 1.76 x 10⁻⁴ N/m.

Learn more about force here: https://brainly.com/question/12970081

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