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All the offspring from the cross illustrated will be heterozygous for the trait.
Assuming the seed shape allele is represented by the allele A (a).
Homzygous dominant = AA
Homzygous recessive = aa
Crossing AA and aa:
AA x aa
Aa Aa Aa Aa
Thus, all the offspring will be heterozygous for the seed shape trait.
More on monohybrid crossing can be found here: https://brainly.com/question/15314052
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