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Given: ΔABC (to the right)
AB=15
BD=9
AD⊥BC
m∠C=30°
Find Perimeter of ABC

Given ΔABC To The Right AB15 BD9 ADBC MC30 Find Perimeter Of ABC class=

Sagot :

Akposevictoridn

Applying the Pythagorean theorem and the trigonometric ratios, the perimeter of triangle ABC is: 68.8 units.

What is the Perimeter of a Triangle?

The perimeter of a triangle = sum of its 3 sides.

Given the following:

  • AB = 15
  • BD = 9
  • m∠C=30°

Use the Pythagorean theorem to find AD considering triangle ADB as a right triangle:

AD = √(15² - 9²)

AD = 12 units

Use the trigonometric ratios to find DC and AC:

sin 30 = AD/AC

sin 30 = 12/AC

AC = 12/sin 30

AC = 24 units

tan 30 = AD/DC

tan 30 = 12/DC

DC = 12/tan 30

DC ≈ 20.8 units

BC = BD + DC = 9 + 20.8

BC = 29.8 units.

Perimeter of triangle ABC = BC + AB + AC

Perimeter of triangle ABC = 29.8 + 15 + 24

Perimeter of triangle ABC = 68.8 units.

Learn more about the perimeter of a triangle on:

https://brainly.com/question/24382052

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