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Suppose the length and the width of the sandbox are doubled.

Suppose The Length And The Width Of The Sandbox Are Doubled class=

Sagot :

The percentage change in perimeter is 100%.

The percentage change in area is 300%

How to find perimeter and area?

The perimeter of the sandbox = 2l + 2w

where

  • l = length
  • w = width

Therefore,

perimeter = 2(10) + 2(6)

perimeter = 20 + 12 = 32 ft

The area of the sand box = lw

area = 10 × 6 = 60 ft²

If the length and width are doubled,

length = 2(10) = 20 ft

width = 2(6) = 12 ft

hence,

perimeter = 2(20) + 2(12) = 40 + 24 = 64 ft

area = 12 × 20 = 240 ft²

Therefore,

percentage change in perimeter = 64 - 32 / 32 × 100 = 100%

percentage change in area = 240 - 60 / 60 × 100 = 18000 / 60 = 300%

learn more on perimeter and area here: brainly.com/question/15322533

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