Find the best solutions to your problems with the help of IDNLearn.com. Discover prompt and accurate answers from our experts, ensuring you get the information you need quickly.
The force required to punch a hole 1 cm in diameter in a steel sheet is 0.176 x 10¹³ N.
The force is defined as the shear stress or pressure applied per unit area.
F = P/A
Given is a steel sheet whose thickness t = 5mm = 5x 10⁻³ m, shearing strength P = 2.76 × 10⁸ N/m², diameter of hole d = 1cm = 1x 10⁻² m
The area to be punched A = πd xt
A = π x 1x 10⁻² x5x 10⁻³
A = 15.7 x 10⁻⁵ m²
The force required to punch a hole is
F = 2.76 × 10⁸ / 15.7 x 10⁻⁵
F = 0.176 x 10¹³ N.
Thus, the punching force is 0.176 x 10¹³ N.
Learn more about force.
https://brainly.com/question/21763500
#SPJ1