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We are asked to solve the equation [tex]\large\pmb{39y=4y+11}[/tex].
[tex]\triangle~\fbox{\bf{KEY:}}[/tex]
First, subtract 4 from both sides of the equal sign:
[tex]\pmb{39y-4y=11}[/tex]
Which gives us:
[tex]\pmb{35y=11}[/tex]
Divide both sides by 35:
[tex]\pmb{\cfrac{35}{11}}[/tex]
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