Laderricka4idn
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what three consecutive odd integers have a sum of 64. show steps please

Sagot :

LammettHashidn

There are no such integers. Odd + odd = even, and adding odd to that makes it odd again. But 64 is even.

Put another way, let n be the smallest of the three integers. Then

n + (n + 2) + (n + 4) = 64

3n + 8 = 64

3n = 56

But 3 does not divide 56, so there is no integer solution for n.

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