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A line is parallel to y=-2x-5 and intersects the point (-1,3) input the correct values into the point slope formula y-[?] = [__}(x- [__])

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ShubhamchouhanvrVTidn

The equation of the line parallel to y=-2x-5 and passing through the point (-1,3) is y = -2x + 1.

What is an equation?

It is defined as the relation between two variables, if we plot the graph of the linear equation we will get a straight line.

Given that:-

  • A line is parallel to y=-2x-5 and intersects the point (-1,3)

The equation of the new line will be:-

y - y₁ = m ( x - x₁ )

Since the line is parallel to the line y = -2x - 5 so slope will be same m = -2 now the coordinates are ( -1, 3).

y - ( 3) = -2 [( x - (-1) ]

y - 3 = -2x - 2

y = -2x + 3 -2

Y = -2x + 1

Therefore the equation of the line parallel to y=-2x-5 and passing through the point (-1,3) is y = -2x + 1.

To know more about equations follow

https://brainly.com/question/2972832

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