Find the best answers to your questions with the help of IDNLearn.com's knowledgeable users. Ask your questions and get detailed, reliable answers from our community of experienced experts.

Please HELP!!!! Im stuck!

Please HELP Im Stuck class=

Sagot :

The  enthalpy of the reaction, [tex]S_{(s)} + O_{2}_{(g)} \rightarrow SO_{2}_{(g)}[/tex], ΔH is -197 kJ.

What is the enthalpy change of the reaction?

The enthalpy change of a reaction, ΔH, is the heat absorbed or given off when reactants form products for a given reaction.

The enthalpy change, ΔH, of the reaction given below:

[tex]S_{(s)} + O_{2}_{(g)} \rightarrow SO_{2}_{(g)}[/tex]

The enthalpy change is calculated from the intermediate reactions:

[tex]S_{(s)} + \frac{3}{2}\:O_{2}_{(g)} \rightarrow SO_{3}_{(g)} \:\Delta H_{1} = -395.2 \:kJ\\SO_{3}_{(g)}\rightarrow SO_{2}{(g)} + \frac{1}{2}O_{2}_{(g)} \:\Delta H_{2} = 198.2\:kJ[/tex]

ΔH = ΔH₁ + ΔH₂

ΔH = -395.2 + 198.2 kJ

ΔH = -197 kJ

Therefore, the enthalpy of the reaction, [tex]S_{(s)} + O_{2}_{(g)} \rightarrow SO_{2}_{(g)}[/tex], ΔH = -197 kJ.

Learn more about enthalpy at: https://brainly.com/question/14291557

#SPJ1