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Sagot :
8v + 3 -4v = 4v + 5 -3 has infinitely many solutions
7v - 11 = 7v + 11 has no solution
3(v-4) = 2(v-6) has one solution
5(2v+3) - 2 = 12v + 12 -2v has no solution
When does an equation have one solution, no solution or infinitely many solutions?
A linear equation is said to have infinitely many solution when the variable term and the constant term are the same on both sides of the equation.
A linear equation is said to have no solution, if the coefficient of the variable term is zero and the constant term a non-zero term
A linear equation is said to have one solution if the coefficient of both the constant term and the variable terms are no zero.
Analysis:
8v + 3 -4v = 4v + 5-2
4v +3 = 4v+3
The equation has an infinitely many solutions
7v-11 = 7v+11
7v-7v = 11+11
0v = 22
The equation has no solution since the coefficient of the variable term is 0
3(v-4) = 2(v-6)
3v -12 = 2v - 12
v = 12-12 = 0
The equation has one solution
5(2v+3) -2 = 12v + 12-2v
10v+15-2 = 10v +12
0v = -1
The equation has no solution.
In conclusion,
8v + 3 -4v = 4v + 5 -3 has infinitely many solutions
7v - 11 = 7v + 11 has no solution
3(v-4) = 2(v-6) has one solution
5(2v+3) - 2 = 12v + 12 -2v has no solution
Learn more about equations with infinitely many solutions: brainly.com/question/11695252
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