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Answer:
True.
Keys:
Step-by-step explanation:
[tex]\tan \left(\theta\right)+\cot \left(\theta\right)=\sec \left(\theta\right)\csc \left(\theta\right)\\\tan \left(\theta\right)+\cot \left(\theta\right)\\=\frac{\cos ^2\left(\theta\right)+\sin ^2\left(\theta\right)}{\cos \left(\theta\right)\sin \left(\theta\right)}\\=\frac{1}{\cos \left(\theta\right)\sin \left(\theta\right)}\\\\\sec \left(\theta\right)\csc \left(\theta\right)\\=\frac{1}{\cos \left(\theta\right)\sin \left(\theta\right)}[/tex]
What was shown throughout this problem?
We showed that two different sides are capable of taking the same form.