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A café owner is designing a new menu and wants to include a decorative border around the outside of her food listings. Due to the cost of
printing, the border should have an area of 48 square inches. The width of the border needs to be uniform around the entire menu. She has
already determined that her food listings will fit within a 13-inch by 9-inch rectangular area.
13 in
9 in
The area of the decorative border can be modeled by the following equation, where x represents the width of the decorative border.
x²+
X=
Is it reasonable for the border to be 2.5 inches wide?
(yes/no)

Type The Correct Answer In Each Box Spell All Words Correctly And Use Numerals Instead Of Words For Numbers If Necessary Use For The Fraction Bars A Café Owner class=

Sagot :

The equation is x² + 11x = 12. Here x represents the width of the decorative border and no, it is not reasonable to be 2.5 inches wide.

What is the area of the rectangle?

It is defined as the area occupied by the rectangle in two-dimensional planner geometry.

The area of a rectangle can be calculated using the following formula:

Rectangle area = length x width

We have an area of border  48 square inches.

Menu dimensions without border =  13-inch by 9-inch

The area of the border can be expressed by the equation:

area of border = area of rectangle with border—area of rectangle without

                            border

48 = (13 + 2x)(9 + 2x) - 13×9

[tex]\rm 48=4x^2+44x[/tex]

After simplification:

[tex]\rm 4x^2+44x-48=0[/tex]

or

x² + 11x = 12

Find the solution of the above quadratic equation:

x = 1 or x = -12(width cannot be negative)

Width should be 1 inches.

We have given x = 2.5 it is not reasonable for the border to be 2.5 inches wide. Due to the cost of printing, the border should have an area of 48 square inches.

Thus, the equation is x² + 11x = 12 here x represents the width of the decorative border and no, it is not reasonable to be 2.5 inches wide.

Learn more about the area of a rectangle here:

https://brainly.com/question/15019502

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