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[tex]~~~~~~ \textit{Simple Interest Earned Amount} \\\\ A=P(1+rt)\qquad \begin{cases} A=\textit{accumulated amount}\dotfill & \$6000\\ P=\textit{original amount deposited}\\ r=rate\to 9.5\%\to \frac{9.5}{100}\dotfill &0.095\\ t=years\dotfill &2 \end{cases} \\\\\\ 6000=P[1+(0.095)(2)]\implies \cfrac{6000}{1.19}=P\implies 5042.02\approx P[/tex]