Need help with math asap

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07-06-2022
Mathematics

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Need help with math asap

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Loneguyidn Loneguyidn · Answer 1 · 2022-06-07T18:06:56-04:00

Loneguyidn Loneguyidn

07-06-2022

[tex]~~~~~~~\tan \theta = \dfrac{\text{Perpendicular}}{\text{Base}}\\\\\\\implies \tan \theta = \dfrac{LN}{LM}\\\\\\\implies \theta = \tan^{-1} \left( \dfrac{LN}{LM} \right)\\\\\\\implies \theta = \tan^{-1} \left(\dfrac{12.81}{7.72} \right)\\\\\\\implies \theta =58.92^{\circ}[/tex]

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