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Find the value of x. (4x-101) (2x+3)
A. 31
B.107
C.52
D.46

Sagot :

(4x−101)(2x+3)

Apply the distributive property by multiplying each term of 4x−101 by each term of 2x+3.

8x²+12x−202x−303

Combine 12x and −202x.

8x²−190x−303

Hi student, let me help you out! :)

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We are asked to find the value of x in [tex]\mathrm{(4x-101)(2x+3)}[/tex].

◈ Note:

⇛ We can't find the value of x, but we can simplify this expression.

This is how we'll simplify it:

◆ Multiply 4x times 2x and 3 first:

[tex]\large\pmb{4x\times2x=8x^2}[/tex]

[tex]\large\pmb{4x\times3=12x}[/tex]

Add the terms:

[tex]\large\pmb{8x^2+12x}[/tex]

Now, do the same thing with -101 - multiply that times 2x and 3:

[tex]\large\pmb{-101\times2x=-202x}[/tex]

[tex]\large\pmb{-101\times3=-303}[/tex]

Add the terms:

[tex]\large\pmb{-202x-303}[/tex]

Put all 4 of the terms together:

[tex]\large\pmb{8x^2+12x-202x-303}[/tex]

Combine like terms (12x and -202x):

[tex]\large\pmb{8x^2-190x-303}[/tex]

Hope it helps you out! :D

Ask in comments if any queries arise.


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