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The hydrogen emission spectrum is shown below. What is the energy of the
410 nm emission line? (The speed of light in a vacuum is 3.00 x 108 m/s, and
Planck's constant is 6.626 x 10-34 J.s.)
400
750 pm

The Hydrogen Emission Spectrum Is Shown Below What Is The Energy Of The 410 Nm Emission Line The Speed Of Light In A Vacuum Is 300 X 108 Ms And Plancks Constant class=

Sagot :

CrystalQueenidn

Answer:

C.) 4.85 x 10⁻¹⁹ J

Explanation:

To find the energy, you need to use the following equation:

E = hc / w

In this formula,

-----> E = energy (J)

-----> h = Planck's Constant (6.626 x 10⁻³⁴ J*s)

-----> c = speed of light (3.00 x 10⁸ m/s)

-----> w = wavelength (m)

Once you have converted nanometers to meters, you can plug the given values into the equation and solve.

410 nm                1 m
-------------  x  ----------------------  =  4.10 x 10⁻⁷ m
                        1 x 10⁹ nm

E = hc / w

E = (6.626 x 10⁻³⁴ J*s)(3.00 x 10⁸ m/s) / (4.10 x 10⁻⁷ m)

E = 4.85 x 10⁻¹⁹ J

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