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How many gallons of a 60% antifreeze solution must be mixed with 70 gallons of 15% antifreeze to get a mixture that is 50% antifreeze?

Sagot :

AshishdwivedilVTidn

There are 245 gallons of antifreeze solution required.

What is Percentage?

Percentage can be calculated by dividing the value by the total value, and then multiplying the result by 100.

Here, Let 60% antifreeze solution  volume = x

15% antifreeze solution volume = 15%

Final concentration 50%

Process

             0.6x + 0.15(70) = 0.5(70 + x)

Simplification

                 0.6x + 10.5 = 35 + 0.5x

                 0.6x - 0.5x = 35 - 10.5

                          0.1x = 24.5

                             x = 24.5/0.1

                            x = 245 gallons

Thus, There are 245 gallons of antifreeze solution required.

Learn more about Percentage from:

https://brainly.com/question/15308590

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