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Sagot :
Detailed Answer:
Let ‘n’ be the middle term of three consecutive even integers. Therefore, (n) is also an even number. Hence, the even number preceding it will be (n - 2) and the even number after it will be (n + 2), since we need consecutive even integers.
Hence, we have (n - 2), (n), (n + 2).
Sum of the Integers :-
= (n - 2) + (n) + (n + 2)
= n - 2 + n + n + 2
= n + n + n + 2 - 2
= n + n + n
=> 3n
Let ‘n’ be the middle term of three consecutive even integers. Therefore, (n) is also an even number. Hence, the even number preceding it will be (n - 2) and the even number after it will be (n + 2), since we need consecutive even integers.
Hence, we have (n - 2), (n), (n + 2).
Sum of the Integers :-
= (n - 2) + (n) + (n + 2)
= n - 2 + n + n + 2
= n + n + n + 2 - 2
= n + n + n
=> 3n
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