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[tex]\quad \huge \quad \quad \boxed{ \tt \:Answer }[/tex]
[tex]\qquad \tt \rightarrow \: f(0) = -2[/tex]
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[tex] \large \tt Solution \: : [/tex]
[tex]\qquad \tt \rightarrow \: 2 {x}^{2} - 3y = 6[/tex]
[tex]\qquad \tt \rightarrow \: 3y + 6 = 2 {x}^{2} [/tex]
[tex]\qquad \tt \rightarrow \: 3y = 2 {x}^{2} - 6[/tex]
[tex]\qquad \tt \rightarrow \: y = \cfrac{2 {x}^{2} - 6 }{3} [/tex]
[tex]\qquad \tt \rightarrow \: y = \cfrac{2 {}^{} }{3} {x}^{2} - 2[/tex]
[ here, y can be replaced with f(x) because y is a function of x ]
[tex]\qquad \tt \rightarrow \: f(x) = \cfrac{2 {}^{} }{3} {x}^{2} - 2[/tex]
[tex] \large\textsf{Find f(0):} [/tex]
[tex]\qquad \tt \rightarrow \: f(0) = \cfrac{2 {}^{} }{3} {(0)}^{2} - 2[/tex]
[tex]\qquad \tt \rightarrow \: f(0) = 0 - 2[/tex]
[tex]\qquad \tt \rightarrow \: f(0) = - 2[/tex]
Answered by : ❝ AǫᴜᴀWɪᴢ ❞