Answered

Join the IDNLearn.com community and get your questions answered by experts. Discover comprehensive answers to your questions from our community of knowledgeable experts.

If 44.7 g of KCI (MM = 74.55 g/mol) are added to a 500.0 mL volumetric flask, and water is added to fill the flask, what is the concentration of KCI in the resulting solution?

If 447 G Of KCI MM 7455 Gmol Are Added To A 5000 ML Volumetric Flask And Water Is Added To Fill The Flask What Is The Concentration Of KCI In The Resulting Solu class=

Sagot :

1.199 M is the concentration of KCI in the resulting solution.

What are moles?

A mole is defined as 6.02214076 × [tex]10^{23}[/tex] of some chemical unit, be it atoms, molecules, ions, or others. The mole is a convenient unit to use because of the great number of atoms, molecules, or others in any substance.

No.of moles of KCI

[tex]Moles = \frac{mass}{molar \;mass}[/tex]

[tex]Moles = \frac{44.7 g}{74.5513 g/mol}[/tex]

= 0.599 moles

Vol.of the solution,V= 500 ml

= 0.5 liter

Molarity

[tex]Molality = \frac{Moles \;solute}{Volume \;of \;solution \;in \;litre}[/tex]

[tex]Molality = \frac{0.599 moles}{0.5 liter}[/tex]

= 1.199 M

Hence, 1.199 M is the concentration of KCI in the resulting solution.

Learn more about moles here:

https://brainly.com/question/8455949

#SPJ1

We appreciate your participation in this forum. Keep exploring, asking questions, and sharing your insights with the community. Together, we can find the best solutions. Your questions deserve accurate answers. Thank you for visiting IDNLearn.com, and see you again for more solutions.