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What is the slope of the line passing through the points (−3, −5) and (−1, −6)?

−4/3

−1/2

1/2

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Sagot :

Answer:

The slope of the line passing through the points (−3, −5) and (−1, −6) is [tex]-\frac{ 1 }{ 2 }[/tex] (-0.5)

Step-by-step explanation:

Equation of a straight line:

y = mx + b where m is the slope and b is the y-intercept

(x1, x2) and (y1, y2) : (−3, −5) and (−1, −6)

Calculating Slope (m).

m = [tex]\frac{y_{2} - y_{1}}{x_{2} - x_{1}}[/tex]

m = [tex]\frac{ (-6) - (-5) }{ (-1) - (-3) }[/tex]

m = [tex]\frac{ -6 + 5 }{ -1 + 3 }[/tex]

m = [tex]-\frac{ 1 }{ 2 }[/tex]

we can take this a step further by finding the equation:

Now putting value of m in equation (i)

y = -0.5x + b

Calculating Y-intercept (b).

Lets choose the first point, (-3,-5) for calculating y-intercept:

y = mx + b

-5 = -0.5(-3) + b

-5 = 1.5 + b

-6.5 = b

b = -6.5

Now putting value of b in equation

y = -0.5x + -6.5

Answer:

-1/2

Step-by-step explanation:

m=(y2-y1)/(x2-x1)

m=(-6-(-5))/(-1-(-3))

m=(-6+5)/(-1+3)

m=-1/2