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What is the molar concentration of
a solution with a volume of 1.5 L
containing 660 g Ca3(PO4)2?

What Is The Molar Concentration Of A Solution With A Volume Of 15 L Containing 660 G Ca3PO42 class=

Sagot :

Brentvanmeleidn

Answer:

1.42 M

Explanation:

First calculate the amount of moles.

that's done by dividing the mass with the molecular mass so 660g / 310.18 g/mol = 2.13 mol

Then you can calculate the molarity by dividing the moles with the volume so 2.13 mol / 1.5 l = 1.42 M

(without rounding: 1.418531175 M)

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