Answer:
[tex]\huge\boxed{\sf Current = 6\ Ampere}[/tex]
Explanation:
In a parallel circuit, Total resistance is:
[tex]\displaystyle \frac{1}{R_T} =\frac{1}{R_1} +\frac{1}{R_2}[/tex]
Where [tex]R_1[/tex] = 6Ω and [tex]R_2[/tex] = 12Ω
Finding [tex]R_T\\[/tex]:
[tex]\displaystyle \frac{1}{R_T} =\frac{1}{6} +\frac{1}{12} \\\\\frac{1}{R_T} =\frac{1 \times 2+1}{12} \\\\\frac{1}{R_T} =\frac{3}{12} \\\\\frac{R_T}{1} = \frac{12}{3} \\\\\boxed{R_T=4 \ Ohm}[/tex]
Finding current:
We know that:
V = IR (Ohm's Law)
V = 24 V, R = 4 Ω (V given, R found)
24 = I(4)
Divide 4 to both sides
6 A = I
Current = 6 Ampere
[tex]\rule[225]{225}{2}[/tex]
